Compounded Sterile Preparation Technician (CSPT) Practice Exam 2025 – Your All-in-One Guide to Success!

Question: 1 / 400

How much Sodium Chloride 23.4% is required to prepare 0.9% NS?

10 mls

3.84 mls

To determine how much Sodium Chloride 23.4% is needed to prepare a 0.9% Normal Saline (NS) solution, it's essential to understand the concept of dilution and concentration.

First, 0.9% NS means that there are 0.9 grams of sodium chloride in 100 mL of solution. When using a concentrated solution, like 23.4% Sodium Chloride, it is important to convert this percentage into grams per milliliter. A 23.4% solution contains 23.4 grams of sodium chloride in 100 mL, or 0.234 grams per milliliter.

To calculate the volume of the 23.4% solution needed to obtain the desired amount of sodium chloride for the 0.9% NS solution, the formula used is:

C1V1 = C2V2

Where:

- C1 is the concentration of the stock solution (23.4% or 234 mg/mL),

- V1 is the volume of the stock solution needed,

- C2 is the concentration of the desired solution (0.9% or 9 mg/mL),

- V2 is the volume of the final desired solution (commonly

Get further explanation with Examzify DeepDiveBeta

50 mls

100 mls

Next Question

Report this question

Download Compounded Sterile Preparation Technician (CSPT) Practice Exam 2025 – Your All-in-One Guide to Success! PDF Study Guide
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy